A //\ / / /|\ / / / | \ / / / | \ / / / | \ C---------/----/----|----\B M K D

Given: triangle ABC; altitude AD; angle bisector AK; median AM angle CAM=MAK=KAD=DAB (all the four smaller angles forming BAC are equal)

Prove: angle BAC is a right angle

[excuse the inaccuracy of the drawing]

2/2/95

Matt Buas

<send proofs to <mbuas@cap.gwu.edu>

-this is a really interesting problem, it took me a long while to solve, i'd be curious to see different proofs